(x^3+x^2+2x-4)/(x-1)

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Solution for (x^3+x^2+2x-4)/(x-1) equation: 


D( x )

x-1 = 0

x-1 = 0

x-1 = 0

x-1 = 0 // + 1

x = 1

x in (-oo:1) U (1:+oo)

(x^3+x^2+2*x-4)/(x-1) = 0

x^3+x^2+2*x-4 = 0

x^3+x^2+2*x-4 = 0

{ 1, -1, 2, -2, 4, -4 }

1

x = 1

x^3+x^2+2*x-4 = 0

1

x-1

x^2+2*x+4

x^3+x^2+2*x-4

x-1

x^2-x^3

2*x^2+2*x-4

2*x-2*x^2

4*x-4

4-4*x

0

x^2+2*x+4 = 0

DELTA = 2^2-(1*4*4)

DELTA = -12

DELTA < 0

x in { 1} 

x-1 = 0

1 = 0

x belongs to the empty set

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